Obviously what you state is correct. Otherwise nothing would work. However,
if the load end is shorted to ground, then the voltage drop across the wire
will be close to the source voltage, provided the power supply can provide
the required current. If the wire opens up then of course it will no longer
be carrying any current but the voltage across it will still be the source
voltage as measured from the source to ground. Regards - Mike
Mike B. Feher, N4FS
89 Arnold Blvd.
Howell NJ, 07731
(732) 901-9193
----- Original Message -----
From: "John Allain" <allain_at_panix.com>
To: "CCTalk" <cctalk_at_classiccmp.org>
Sent: Sunday, November 24, 2002 4:12 PM
Subject: Re: MicroVAX II
> I don't know if anybody said it here yet (I try* to not read the
> list all day long) but the voltage _drop_ of a wire carrying X
> volts isn't X, especially for the purposes of calculating power
> loss. One of those "You're Both right" kind of things.
Received on Sun Nov 24 2002 - 15:26:00 GMT