Cheetah Cub board

From: Steve Thatcher <melamy_at_earthlink.net>
Date: Wed Jun 9 14:50:55 2004

the little guys are only 256K by 1, so it takes 9 of them to make a 256K byte bank. PC memory has always been spoken off by the byte.

As for the Amiga, it will take 8 (or 9) to make each 256K byte upgrade. Of course, getting nit picky, 256K bytes could be thought of as a 2meg bit upgrade - it sounds impressive and it what a saleman would have said... LOL

I can understand your need to stick your face in mud rather than buy a PC... :)

best regards, Steve


-----Original Message-----
From: Doc Shipley <doc_at_mdrconsult.com>
Sent: Jun 9, 2004 3:09 PM
To: Steve Thatcher <melamy_at_earthlink.net>, General_at_mdrconsult.com,
        Discussion_at_mdrconsult.com_at_null,
        On-Topic and Off-Topic Posts <cctalk_at_classiccmp.org>, null_at_null
Subject: Re: Cheetah Cub board

Steve Thatcher wrote:

> hmmm, I thought there were four rows of 18 chips. That sounds like 8 banks of 256K which seems
> like 2meg to me... unless I got something wrong

   No, I guess I got it wrong. I thought you meant 256K per chip, or
4MB per bank (16 * 256K plus 2 * 256K for parity).

   So are these 256K per bank, or 256K per chip? IOW, if they turn out
to be compatible and I install 16 of them on the Amiga A2091, will that
be a 2MB or 0.25MB upgrade?

   I'm a complete retard at memory components. It doesn't make sense to
me at all, even after a fair amount of reading and some explanation from
  some Smart People.

> as for board worth, the 256K chips are worth a bit. I found a site that had them for sale at $0.75 each.

   Well, that wouldn't suck. Of course that means they're really worth
about $0.20/each. :)

> If you need a PC to run it in, buy one on eBay... LOL (couldn't help that one)

   Heh. I'd rather stick my face in the mud.... [family joke]


        Doc
Received on Wed Jun 09 2004 - 14:50:55 BST