Driving a 7805 or how else to get +5VDC reg (was Re: My first good find!!!)

From: Clint Wolff <vaxman_at_earthlink.net>
Date: Sat Dec 7 04:16:01 2002

Hi Ethan,

Most modern DC-DC converters are designed with simplicity in mind. It
doesn't take a slide rule, or a PDP-8 to figure out component values,
they are usually supplied as part of an app-note with the data sheet.

If you go to www.digikey.com, you can execute a parametric search for
'DC converter', select a part that has reasonable characteristics
(voltage in, current/voltage out), and download the data sheet. At
worst you will have to calculate a couple resistors to set the voltage.

Good Luck!

On Fri, 6 Dec 2002, Ethan Dicks wrote:

> > [ACE PSU]
> > ...a 7805 1A linear regulator which needs around
> > 8V to 15V to run properly.
> So I was thinking about this recently... I have this 6V battery
> pack that is intended to clamp to the back of a ZIP drive, allowing
> it to be used away from power, say with a laptop. I've wanted
> to use it for a portable source of juice for hobby projects (it
> has, among other features, a built-in 110V mains plug and recharger,
> making it handy to recharge), but I haven't expected to be able to
> feed a 7805 at +6VDC and get +5VDC out the other side reliably.
> How can I take +6VDC of battery power and get +5VDC regulated power
> from it? If it matters, the currents involved will be under 1000mA,
> but probably over 200mA.
> -ethan
> P.S. - I don't mind the concept of a DC-DC converter, but I'm not
> skilled enough to design one, just skilled enough to build it.
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Received on Sat Dec 07 2002 - 04:16:01 GMT

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